Vera Zvonareva
Height, Weight, Size, Body Measurements, Biography, Wiki, Age

When and where Vera Zvonareva was born?

Age
39 years
Birth date
September 7, 19841984-09-07
Zodiac sign
Virgo
Place of Birth
Russia
Occupation
Tennis player
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Biography (wiki)

Vera Igorevna Zvonareva (Russian: Ве́ра И́горевна Звонарёва, IPA:  (listen); born 7 September 1984) is a Russian professional tennis player. She was introduced to tennis at the age of six and turned professional in 2000. Her career-high ranking is world No. 2 by the WTA. Zvonareva has won twelve WTA Tour singles titles including 2009 Indian Wells Masters and reached the finals of the 2008 WTA Tour Championships, 2010 Wimbledon Championships, and 2010 US Open. She also was a bronze medalist at the 2008 Beijing Olympics. In doubles, she has won four Grand Slam titles. Two of the titles came in women's doubles, the first one at the 2006 US Open, partnering Nathalie Dechy, and the other at the 2012 Australian Open, partnering Svetlana Kuznetsova. Her other two came in mixed doubles, the first at the 2004 US Open, partnering Bob Bryan, and her second at the 2006 Wimbledon Championships, partnering Andy Ram.

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Body Measurements

Height and Weight 2024

How tall and how much weigh Vera Zvonareva?
Height 5 ft 8 in / 172 cm
Weight 130 lb / 59 kg
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Body size

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Bra size
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Appearance

Hair Color Brown
Eye Color Blue
Nationality Russian
Race / ethnicity White

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