Tallon Griekspoor
Height, Weight, Size, Body Measurements, Biography, Wiki, Age
When and where Tallon Griekspoor was born?
| Age |
|---|
| 27 years |
| Birth date |
| July 2, 1996 |
| Zodiac sign |
| Cancer |
| Place of Birth |
| Netherlands |
| Occupation |
| Tennis player |
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Biography (wiki)
Tallon Griekspoor (born 2 July 1996) is a Dutch tennis player.
Griekspoor has a career high ATP singles ranking of 181 achieved on 30 July 2018. He also has a career high ATP doubles ranking of 287 achieved on 1 August 2016.
Griekspoor made his ATP main draw debut at the 2017 ABN AMRO World Tennis Tournament in the singles draw against Gilles Müller. A year later, he defeated Grand Slam champion Stan Wawrinka of Switzerland in three sets to reach the second round. In 2019 Griekspoor defeated the number 11 in the world, Karen Khachanov, in the first round.
Body Measurements
Height and Weight 2024
| Height | 6 ft 2 in / 188 cm |
|---|---|
| Weight | 181 lb / 82 kg |
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Body size
| Breast/Bust size | – |
|---|---|
| Waist size | – |
| Hips size | – |
| Dress Size | – |
| Shoe (Feet) Size | – |
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Breast –
Waist –
Hips –
Appearance
| Hair Color | Blonde |
|---|---|
| Eye Color | Blue |
| Nationality | Dutch |
| Race / ethnicity | White |
Video
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